H=2+45t-16t^2

Solution for H=2+45t-16t^2 equation:

=2+45H-16H^2

We move all terms to the left:

-(2+45H-16H^2)=0

We get rid of parentheses

16H^2-45H-2=0

a = 16; b = -45; c = -2;
Δ = b2-4ac
Δ = -452-4·16·(-2)
Δ = 2153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2153}}{2*16}=\frac{45-\sqrt{2153}}{32}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2153}}{2*16}=\frac{45+\sqrt{2153}}{32}
$